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When running Online DiSC Classic 2.0 Profiles and DiSC Classic 2 Plus Profiles in your EPIC Account, you have the ability to turn on or off Graphs 1 and 2, and the tally box scores.First, a little information about each of the graphs:
Graph 1: These are your 'Most' responses for each of the four scales (D, i, S, and C).
Graph 2: These are your 'Least' responses for each of the four scales.
Graph 3: This graph is the result of combining your 'Most' choices with your 'Least' choices and is used to determine your highest DiSC dimension, Intensity Index scores, and Classical Profile Pattern. (Graph 3 is automatically included in the Online DiSC Classic 2.0 and DiSC Classic 2 Plus Reports).
Tally Box Scores: Shows a summary and the differences of your 'Most' and 'Least' choices for each of the scales.
When assigning an access code for the Online DiSC Classic 2.0 or DiSC Classic 2 Plus Reports, you'll see the Report Options below:
Depending on the options selected above the resulting DiSC report will include one of 4 configurations:
- Graph 3 only
- Graph 3 and Tally Box Scores
- Graphs 1, 2, and 3
- Graphs 1, 2, 3, and Tally Box Scores
Questions about DiSC?
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How do you graph #(x^2-4)/(x^2-9)#?
1 Answer
You find the intercepts and the asymptotes, and then you sketch the graph.
Explanation:
Step 1. Find the #y# -intercepts.
Edgeview 2 52 – cutting edge image viewer windows 10. #y = f(x) = (x^2-4)/(x^2-9)#
The #y# -intercept is at (#0,4/9# ).
Step 2. Find the x-intercepts.
Kingdom rush frontiers hd 1 4. #0 = (x^2-4)/(x^2-9)#
The #x# -intercepts are at (#-2,0# ) and (#2,0# ).
Step 3. Find the vertical asymptotes.
Set the denominator equal to zero and solve for #x# .
There are vertical asymptotes at #x = -3# and #x = 3# .
Step 4. Find the horizontal asymptote.
Both equations are of the second order, so we divide the coefficients of the #x^2# terms.
The horizontal asymptote is at #y=1# .
Step 5. Draw your axes and the asymptotes.
The vertical asymptotes divide the graph into three regions of #x# s.
Step 6. Sketch the graph in the each region.
(a) In the left hand region,
The point at (#-4,1.7# ) is in the second quadrant, so we have a 'hyperbola' above the horizontal asymptote.
(b) In the right hand region,
So we have a mirror-image 'hyperbola' in the first quadrant.
(c) In the middle region, we have
Disk Graph 2 1 3 X 4
The points at (#-1,0.38# ) and (#1,0.38# ) are below the #y# -intercept, so we have an 'inverted parabola' between the vertical asymptotes.
And we have our graph.